tag:blogger.com,1999:blog-7658327038612444004.post3663666894866798499..comments2024-03-19T02:04:29.216+01:00Comments on EL GRAN LIBRO DE LOS ACERTIJOS DE INGENIO: 1003. ADELANTAMIENTO Y CRUCE DE TRENESJesús Escudero Martínhttp://www.blogger.com/profile/05138576623136587133noreply@blogger.comBlogger3125tag:blogger.com,1999:blog-7658327038612444004.post-48422277136555986562016-05-10T00:21:37.871+02:002016-05-10T00:21:37.871+02:00Siendo "v" la velocidad del tren de carg...Siendo "v" la velocidad del tren de carga y "d" la longitud de este:<br />d/(90-v) = 2 [d/(90+v)]<br />(90+v)/(90-v) = 2<br />Luego la velocidad del tren de carga es v=30 km/h.<br />Jesús Escudero Martínhttps://www.blogger.com/profile/05138576623136587133noreply@blogger.comtag:blogger.com,1999:blog-7658327038612444004.post-7434707226482246742016-05-09T23:23:15.867+02:002016-05-09T23:23:15.867+02:0030 km/h.30 km/h.Mmonchinoreply@blogger.comtag:blogger.com,1999:blog-7658327038612444004.post-87341300765785694662016-05-09T20:53:47.634+02:002016-05-09T20:53:47.634+02:00Este comentario ha sido eliminado por el autor.Carlos Feinsteinhttps://www.blogger.com/profile/07611106783101368478noreply@blogger.com